Java Strings Introduction

 A string is traditionally a sequence of characters, either as a literal constant or as some kind of variable." — Wikipedia: String (computer science)

This exercise is to test your understanding of Java Strings. A sample String declaration:

String myString = "Hello World!"

The elements of a String are called characters. The number of characters in a String is called the length, and it can be retrieved with the String.length() method.

Given two strings of lowercase English letters,  and , perform the following operations:

1. Sum the lengths of  and .
2. Determine if  is lexicographically larger than  (i.e.: does  come before  in the dictionary?).
3. Capitalize the first letter in  and  and print them on a single line, separated by a space.

Input Format

The first line contains a string . The second line contains another string . The strings are comprised of only lowercase English letters.

Output Format

There are three lines of output:
For the first line, sum the lengths of  and .
For the second line, write Yes if  is lexicographically greater than  otherwise print No instead.
For the third line, capitalize the first letter in both  and  and print them on a single line, separated by a space.

Sample Input 0

hello
java

Sample Output 0

9
No
Hello Java

Explanation 0

String  is "hello" and  is "java".

 has a length of , and  has a length of ; the sum of their lengths is .
When sorted alphabetically/lexicographically, "hello" precedes "java"; therefore,  is not greater than  and the answer is No.

When you capitalize the first letter of both  and  and then print them separated by a space, you get "Hello Java".

SOLUTIONS:

import java.util.Scanner;

public class Solution {

    public static void main(String[] args) {

        /* Save input */

        Scanner scan = new Scanner(System.in);

        String A = scan.next();

        String B = scan.next();

        scan.close();

        

        /* Sum lengths */

        System.out.println(A.length() + B.length());

        /* Compare lexicographical ordering */

        System.out.println(A.compareTo(B) > 0 ? "Yes" : "No");

        

        /* Print the Strings in desired format */

        System.out.println(capFirstLetter(A) + " " + capFirstLetter(B));

    }

    

    private static String capFirstLetter(String str) {

        if (str == null || str.length() == 0) {

            return "";

        } else {

            return str.substring(0,1).toUpperCase() + str.substring(1);

        }

    }

}