Java If-Else

 In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia

Task
Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, .

Constraints

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: 
 is odd and odd numbers are weird, so we print Weird.

Sample Case 1: 
 and  is even, so it isn't weird. Thus, we print Not Weird.

SOLUTIONS:

import java.io.*;

import java.util.*;

import java.text.*;

import java.math.*;

import java.util.regex.*;

public class Solution {

    public static void main(String[] args) {

        try{

        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

        int N=Integer.parseInt(br.readLine().trim());

        if(N<1||N>100)

            throw new Exception();

        if((N&1)==1)

        {

            System.out.println("Weird");

        }

        else

        {

            if(N>=2&&N<=5)

            {

                System.out.println("Not Weird");

            }

            else if(N>=6&&N<=20)

            {

                System.out.println("Weird");

            }

            else

            {

                System.out.println("Not Weird");

            }

        }

        }

        catch(Exception e)

        {

            e.printStackTrace();

        }

    }

}